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ROR (Super FX): Difference between revisions

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'''ROR''' (Rotate Right) is a [[Super FX]] instruction that rotates the [[source register]] and [[CY|carry flag]] one bit to the right into the [[destination register]].  Bit 0 of S<sub>reg</sub> is shifted into the carry flag.
'''ROR''' (Rotate Right) is a [[Super FX]] instruction that rotates the [[source register]] and [[CY|carry flag]] one bit to the right into the [[destination register]].  Bit 0 of S<sub>reg</sub> is shifted into the carry flag.  A total of 17 bits participate in the rotation.


The source and destination registers should be specified in advance using [[WITH]], [[FROM]], or [[TO]].  Otherwise, R<sub>0</sub> serves as the default.
The source and destination registers should be specified in advance using [[WITH]], [[FROM]], or [[TO]].  Otherwise, R<sub>0</sub> serves as the default.

Revision as of 20:54, 12 July 2024

Basic Info
Addressing Mode Opcode Length ROM Speed RAM Speed Cache Speed
Implied (type 1) 97 1 byte 3 cycles 3 cycles 1 cycle
Flags Affected
B ALT1 ALT2 O/V S CY Z
0 0 0 .

ROR (Rotate Right) is a Super FX instruction that rotates the source register and carry flag one bit to the right into the destination register. Bit 0 of Sreg is shifted into the carry flag. A total of 17 bits participate in the rotation.

The source and destination registers should be specified in advance using WITH, FROM, or TO. Otherwise, R0 serves as the default.

Syntax

ROR

Example

Let:

Sreg : R10
Dreg : R12
CY = 1
R10 = 1d4bh (0001 1101 0100 1011b)

After executing ROR:

CY = 1
R12 = 8ea5h (1000 1110 1010 0101b)

gsu ror.png

See Also

External Links