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ROR (Super FX): Difference between revisions

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'''ROR''' (Rotate Right) is a [[Super FX]] instruction that rotates the [[source register]] and [[CY|carry flag]] one bit to the right into the [[destination register]].  Bit 0 of S<sub>reg</sub> is shifted into the carry flag.  A total of 17 bits participate in the rotation.
'''ROR''' (Rotate Right) is a [[Super FX]] instruction that rotates the value of the [[source register]] and [[CY|carry flag]] one bit to the right into the [[destination register]].  Bit 0 of S<sub>reg</sub> is shifted into the carry flag.  A total of 17 bits participate in the rotation.


The [[ALT0]] state is restored.
The [[ALT0]] state is restored.
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[[File:gsu_ror.png]]
[[File:gsu_ror.png]]
The source register itself is not modified despite the arrows in the above image.


=== See Also ===
=== See Also ===

Revision as of 01:57, 22 August 2024

Basic Info
Addressing Mode Opcode Length ROM Speed RAM Speed Cache Speed
Implied (type 1) 97 1 byte 3 cycles 3 cycles 1 cycle
Flags Affected
B ALT1 ALT2 O/V S CY Z
0 0 0 . S CY Z

ROR (Rotate Right) is a Super FX instruction that rotates the value of the source register and carry flag one bit to the right into the destination register. Bit 0 of Sreg is shifted into the carry flag. A total of 17 bits participate in the rotation.

The ALT0 state is restored.

The source and destination registers should be specified in advance using WITH, FROM, or TO. Otherwise, R0 serves as the default.

Syntax

ROR

Example

Let:

Sreg : R10
Dreg : R12
CY = 1
R10 = 1d4bh (0001 1101 0100 1011b)

After executing ROR:

CY = 1
R12 = 8ea5h (1000 1110 1010 0101b)

gsu ror.png

The source register itself is not modified despite the arrows in the above image.

See Also

External Links